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Post Info TOPIC: Questions on District test


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Questions on District test
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Hello Webmaster or Mr.Jones (whichever you prefer), i just got my district test back today, and here are some questions i don't know the tricks to(i am sorry my coach kept the answer sheet and i can't post the right answers for you)

1. if (9^x) / (3^x) = 27^-2, then x=
(there's gotta be an easy way to do this...)

2. (Estimation) cube root of (28028) x sqrt of (840) x 31=

3. An acute triangle has integer sides of 3, x, and 7 units. the largest value of x is
* i actually remember the answer for this one, it is 7. But how in the world can it be 7??

4. The product of the coefficients of (2a+3b)^2 is

5. 33 (base4) x 22(base 4)=? (base4)
*i know how to do 1 digit multiplication (it's on your website), but i dont' know 2 digit multi.

thank you, and again i apologize for the inconvenience about the answers

Quincy

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#1 - I am not going to tell you.  I want you to figure this one out.  I will start you off though.


(9^x)/(3^x) = (9/3)^x


27 = 3^3


I think I might have even told you too much but I will let you figure this one out from here.



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#2 - I should probably let you figure this one out too but I will be nice this time.


If you want to know where I am coming from read the website under approximating cube roots and approximating square roots.


Now let's brake it up one piece at a time.  The cubed root of 28028 is approximately 30.  To get this cut off the last 3 digits and we are left with 28.  The cubed root of 28 is almost 3.  Add a 0 and we get 30.


The square root of 840 is almost 29.  If you don't know that 29^2 = 841, then you can chop off the last 2 digits and we have 8.  The square root of 8 is almost 3, so we know that it is very close to 30 (add one 0 since we chopped off 2 numbers).  Seeing how 840 is a pretty good distance away from 900 (which we know is 30^2), we can conclude it is pretty close to 29.


We now have 30 x 29 x 31 which is close to 30^3 = 27000.


The actual answer can be between 25928 - 28655.



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#3 - The answer IS 7.


We know an acute triangle has angles less than 90 degrees and an obtuse triangle has an angle more than 90 degrees.  We can use this information for this problem.


If a triangle has a 90 degree angle the following is true:


a^2 + b^2 = c^2


So if we wanted to solve for c (or the side we are looking for), we simply use:


sqrt(a^2 + b^2) = c


BUT, if we want to guarantee that this was an acute triangle then the other side would have to be less than c, and for an obtuse triangle the other side would have to be greater than c.


So we can make the following rules if given 2 sides of a triangle and looking for the third:


For an acute triangle the third side 'c' would have to satisfy:


c < sqrt (a^2 + b^2)


For an obtuse triangle the third side 'c' would have to satisfy:


c > sqrt (a^2 + b^2)


Note:  If the sqrt(a^2 + b^2) is an integer, then the largest value such that it is an acute triangle would be one less than that number.  Alternately, for an obtuse triangle then the smallest value for c would be one more than that number.


Ex [1]  An acute triangle has integer sides of 3, x, and 7 units. the largest value of x is __________.




  1. 1st determine sqrt (3^2 + 7^2) = sqrt(58);


  2. The sqrt(58) is between the number 7 and 8.


  3. The smallest value x can be is 7.


  4. The answer is 7.


  5. If the question had asked for the smallest value of x to make it into an obtuse triangle, the value would be 8.

Ex [2]  An obtuse triangle has integral sides of 5, x, and 12.  The smallest value of x is __________.



  1. sqrt(5^2 + 12^2) = 13.  *You should recognize the pythagorean triple.

  2. The smallest value is one more than 13 or 14.

  3. The answer is 14.

  4. If the question had asked for the largest value of x such that it makes an acute triangle the answer would be 12.

I hope I made myself clear. 



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#4 - This one is a little complicated, but I really believe that on a number sense test, the power will never be anything but 2.


The reason why is because to solve for the product of the coefficients in general would be:


(ax + by)^n = C(n,n)*C(n,n-1)*...*C(n,1)*C(n,0)*a^(nth triangular number)*b^(nth triangluar number).


Which means this will never get very large.  In fact, I don't even think it will get above 2.  Maybe 3, but I don't think so.  So I would stick with n=2.  I will show the formula for n=3 just in case, but chances are it won't be seen.


For n=2 the formula is:


2*a^3*b^3 


For n=3 the formula is:


9*a^6*b^6


As you can see this is unlikely.  But with a=2 and b=1, it is doable  (or vice versa), which makes it possible to show up.  It is even possible to do a=3 and b=1  (which would be 81^2).  If he wanted he could also use the square root of a number or even the cube root of a number like sqrt(5) or cuberoot(3).


Enough of my jabbering.  It is impossible to predict what Mr. White is thinking on this.  If you are reading this Mr. White - WHAT ARE YOU THINKING????  Just kidding.


The answer to this example is 2 x (2^3) x (3^3) = 2*8*27 or 8*54 = 432.



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Last Question:


 I believe most people will tell you just to change to base 10 and then change back to base 4, but that is not how I would do it.  I only do that when I am dividing in a different base, not when I am multiplying.


First treat this like you would normally treat it in base 10.  If I saw 22 x 33 I would change this to be 11 x 66.  Now the problem is easy.  So do the same thing here. 


Now the tricky part.  You do the same thing you normally would do except change everything to base 4.  Let me show you the steps:



  1. Usually, we would write 6.  But in base 4 there are no 6's so we need to change 6 to base 4.  It is 12.  Write 2, carry *1.

  2. 6+6 = 12 + *1 = 13.  In base 4, 13 is 31.  So write 1, carry *3.

  3. 6+*3 = 9.  In base 4, 9 is 21.  Write 21.

  4. The answer is 2112.

Let's look at another example:


Ex [1]  (32 base 5) x (12 base 5) = _________(base 5).



  1. I am assuming you would multiply the same way I would which is found in the Multiplying Numbers section under Multiplying By 12-19.

  2. First, we multiply 2 x 2 = 4.  4 in base 5 is 4.  Write 4.

  3. 2*3 = 6 which is 11 in base 5.  32 (base 5) + 11 (base 5)= 43 (base 5).  Write 43.

  4. The answer is 434.

This style of thinking is more difficult than just multiplying by a single digit, but as you can see it can be done the same way.  If this is difficult to see, I would suggest practicing on them.  If you still can't seem to get it, then I would change to base 10 then change back to base b.


Webmaster


P.S.  I don't mind being called Mr. Jones.  I prefer it to the informal, impersonal "webmaster".  Although I will usually have a signature of webmaster.



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so for my first problem...

9^x / 3^x = 27^ -2

(9^x)/(3^x) = (9/3)^x

27 = 3^3

so.... 3^x=(3^3)^-2

x= -6

pretty sure that's right, the part i didn't know was (9^x)/(3^x) equals (9/3)^x...i guess i need lots of practice on this type of problem.

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and for my 3rd problem, the part i am confused on is the way the problem was stated:

3. An acute triangle has integer sides of 3, x, and 7 units. the largest value of x is

like you said, the formula is:
c < sqrt (a^2 + b^2)

BUT...how do you know which value is C?

the order of numbers in the problem is : 3, x, and 7. I always thought that the last value is always c, the largest leg, so when i was taking the test, because i thought 7 was c, i did

x

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er...somehow my message got cut off and i can't figure out why...sorry, but what i meant to say was that i am having trouble determining which value is the C, the Hypotenuse...

p.s.: on the member info, it says that your location is Beijing, China?? Are you in China right now? sorry that's totally not numbersense but since i am Chinese...just wondering


Quincy

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Actually, I had that same question.  Usually when doing these problems, the question will ask it such that the last value is c. 


But my reasoning was this.  I am looking for the largest possible value for x.  That means if I treat x as a leg I will not get as high a number as if  treated it as the hypotenuse.


Just because the problems usually state the legs in order does not mean they have to.  After thinking on it I might be wrong about the obtuse triangle, but I am pretty sure about the acute triangle.  If it is acute, always treat the missing value as the hypotenuse.  I will look to see about the obtuse triangle.  Very good question.


As for your other question, I am currently in Beijing.  We (my wife and I) have lived here for almost 2 years now, thinking about staying for a 3rd.  Of all things, I am an English teacher here.  Since I can only understand a little Chinese (not enough to follow the television) I have to find other ways of using my time.  So I thought I would work on a website.  Are you really Chinese?  Do you understand Chinese, because from the way you write, you have EXCELLENT English skills, which is unusual for a native Chinese.


Webmaster



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Wow! Ni Hao Ma? :)
yep! i am 100% pure native chinese living in TX right now...been here for 5 yrs, man...i gotta meet you sometimes during the summer(i am going back to china this summer, no kidding, and i liave in Beijing too)! Where do you live? I can teach you chinese and u can teach me numbersense during the summer(evil grin....)

Quincy

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Ni hao. 


How do you say "Heck Yeah" in Chinese?  If you come for the summer you can definitely look us up.  We are teachers at "Hua gong da xue" or the Beijing University of Chemical Technology.  We are hopefully going to be here for the summer and we would love (my wife especially) to get some real Chinese lessons.  And you already know I love number sense.  I would love to be your teacher.  How old are you anyway and what school are you with? 


If you do come, I might even be able to write up some sample tests for you if I have enough time.


Zai jian,


Webmaster


P.S.  Does your family know English?  Maybe I can look them up or give them a call.



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"heck yeah"= dang ran la, i am a sophomore(16) and with Harker Heights High School, "hua gong da xue" is actually not far from my house, but what is your address though? because i dont' think you want me to go to your workplace and look for you. :) i am going back in late May. (this summer is going to be great)

Quincy

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i am sorry no one in my family speaks english(my parents and i are the only ones, and we're all in U.S.)

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Oh well,


I hope to see you this summer anyway.



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hehehe...


I live in Yinghua Yuan which is a small alley between Yinghua dongjie and Yinghua xijie, about .5km north of Bei san huan.  It is just north of Heping Li


We can work out the details as time gets nearer.


By the way, my wife said "dang ran la" means "of course".  That is not a fair translation.  A more fair translation would be "What are you thinking, of course the answer is yes!"



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